3 questions on g-factor

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  • #4227 Score: 0
    WoutStoffels
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    1a) For 0 keV, we find I=1/2 and mu = -0.594 nm. We can apply g = mu * hbar / mu_N I = -1.188 nm*hbar*mu_N.
    For 245 keV, the calculation is idetical but with mu = -0.766 and I=5/2. So in this case g = -0.306 nm*hbar*mu_N.

    1b) A free electron has I = 1/2. Since the magnetic moment is only due to the spin (I think), the value for g is g = + 2 * mu_B * hbar / mu_N.

    1c) In this case, we apply mu = g * I * mu_N / hbar. I is 1/2 for the neutron as well, so mu = -1.913 mu_N / hbar.

    #4228 Score: 0
    WoutStoffels
    Participant

    Small correction: I forgot spins are expressed in units of hbar, so the end results in all cases should not contain the factor hbar anymore

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