Complications without multipole expansion

homepage Forums a nucleus with a general shape ? Complications without multipole expansion

Viewing 1 post (of 1 total)
  • Author
    Posts
  • #2701 Score: 0
    Vince Hendriks
    Participant

    If we want to use perturbation theory we want to have a small correction term to a known Hamiltonian as our perturbation. For a general shape we might not be able to get a small perturbation from our interaction term. But expressing it as a multipole expansion, we can use higher-order terms, which are generally small, as a perturbation.

Viewing 1 post (of 1 total)
  • You must be logged in to reply to this topic.