Complications without multipole expansion

homepage Forums a nucleus with a general shape ? Complications without multipole expansion

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    Vince Hendriks

    If we want to use perturbation theory we want to have a small correction term to a known Hamiltonian as our perturbation. For a general shape we might not be able to get a small perturbation from our interaction term. But expressing it as a multipole expansion, we can use higher-order terms, which are generally small, as a perturbation.

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