Energy corrections due to finite size of the nucleus

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    Robin Vrielynck
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    We have seen that there are two contributions:

    1. Fermi contact contribution:
    This contribution will be vanished in this case, because all charges stay outside the nucleus. There cannot be an imbalance of spin-oriented electrons inside the nucleus in our case.

    2. Bohr-Weisskopf effect
    This contribution will not vanish due to the non-zero radius, because this effect depends on the radius of the nucleus.

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