1. 0.8 times the bohr magneton and the magnetic field makes an energy splitting of delta E=0.093meV
2. We first calculate A which is 427 neV.
Then for m_j = +-3/2 this splitting equals 640neV and for m_j=+-1/2 this is 213neV.
The photon energy is thus changes by 640-213neV=427neV
E_photon is thus 93427neV or 92573neV for the transition between -3/2 and -1/2
For -1/2 to 1/2 this energy changes with 427neV too. The photon energies are the same as previous transition