EPR energies

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    Clara
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    Test

    #3917 Score: 0
    Clara
    Participant

    g=1, I=1/2, B_0=2T
    1) Without hf interaction:
    E(m_J)=-g_J \mu_B B_0 m_J
    => E_photon = \Delta E=-g_J \mu_B B_0 \Delta m_J
    -Case of transition between m_J=-3/2 and m_J=-1/2:
    E_photon,1= -g_J \mu_B B_0 (-1) = 0.16 meV.
    -Case of transition between m_J=-1/2 and m_J=+1/2:
    E_photon,2= -g_J \mu_B B_0 (-1) = 0.16 meV.

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