* without hyperfine interaction
E = g*muB*B0*mJ
mJ=1/2: E = -muB
mJ=-1/2: E = muB
mJ=-3/2: E = 3muB
So:
mJ=-1/2 –> 1/2: delta(E) = 2muB
mJ=-3/2 –> -1/2: delta(E) = 2muB
* with hyperfine interaction (Bhf = 10T)
A*mI*mJ = g*muN*Bhf/J *mI*mJ = 20/3 * muN * mI*mJ
with mI = +/-1/2
So:
mJ=-1/2 –> 1/2: energy levels split in two:
From (10/3+5/3)muN –> (-10/3-5/3)muN: delta(E) = 10muN
From (10/3-5/3)muN –> (-10/3+5/3)muN: delta(E) = 10/3*muN
mJ=-3/2 –> 1/2: energy levels split in two:
From (-10+5)muN –> (-10/3+5/3)muN: delta(E) = 10/3 muN
From (-10-5)muN –> (-10/3-5/3)muN: delta(E) = 10*muN