# experimental routine

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• #3586 Score: 0
NoetherTheorem
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First of all one shall keep the magnetic field B_J unchanged. J is independent by its nature from I. For a is a constant and is defined:

a = (\mu_i * B_J)/(I_i * J)

If one is given I_1, \mu_1, and I_2. The constant can not vary its value, what has been already told.

So:

(\mu_1 * B_J)/(I_1 * J) = a = (\mu_2 * B_J)/(I_2 * J)

One obtains:

\mu_1/I_1= \mu_2/I_2, what yields \mu_2 = (I_2/I_1) * \mu_1 q.e.d.

#3587 Score: 0
NoetherTheorem
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Considered are isotopes, so additional neutrons won’t change the electron cloud distribution. In experiment one can but obtain
different but similar values a_1 and a_2. Credits to Johanna Waltenspiel, I’ve understood that thanks to her. It is cosy to assume a_1/a_2 is almost exact unity.

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