Fe-I: I find 3 rotation axes, all 4-fold. These three axes are thus the PAS of the EFG tensor. Also, there is axial symmetry around all these axes. Furthermore, since there are two or more 4-fold axes, the EFG tensor is zero.
edit: I didn’t specify where the axis are:
– Fe-I: along the sides of the cube (orthogonal)
– Fe-II: through Fe-IIb and N, and its two orthogonal axes through Fe-IIa and N
This topic was modified 2 years, 2 months ago by sanfvers.