finite size corrections

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    If the electron charges stay outside the nucleus then the Fermi-contact contribution will not play a role. For the other energy correction, one looks at an integral over the volume of the nucleus. The expression in the notes/video do not say something special about the shape of the nucleus. Only that some volume regions of the nucleus will contribute more to the nuclear magnetic moment than others. The exact shape of the nucleus does not seem to be an important feature of this contribution. So I would say that there would indeed be an energy correction.

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