finite size corrections

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    Brent Van Neste

    No electrons enter the nucleus so there will be no overlap between the charge distributions of the electron cloud and nucleus. Therefore there is no monopole shift.

    No electrons enter the nucleus so the Fermi contact contribution to the hyperfine field is zero. The orbital and spin dipole contributions are still there. This means there will still be a dipole contribution (interaction nuclear magnetic moment and hyperfinefield generated by electron cloud).

    However the still existing contributions mentioned above do not depend on the non finite size of the nucleus (if I understand correctly).
    There still is the Bohr-Weisskopf effect, which does depend on the size on the nucleus, but this effects shows up when we compare ratios of energies of isotopes. I am not sure if this effect is present in this example.

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