Alot of people seem to be missing out the factor of the nuclear magneton, muN.
g = (mu hbar) / (I muN)
This applied to g.s gives: -2.47E-8
Applied to 245Kev state gives: -6.37E-9
For the free electron part, we only need to consider the spin component as it would have no orbital angular momentum as it is not in an orbit. Therefore using:
gs = -(2 me muS) / (S e)
For the free neutron part, simply rearrange the eqn from part one and sub in the numbers to give: