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  • #2302 Score: 0
    jefdryck
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    Lowest level:
    J is given (see picture) by 3/2
    We have only one unfilled (sub)shell (5d) with only one electron. Therefore S = 1/2.
    If less than half of the subshell is filled, J is given by |L-S|, therefore L is 2
    This gives a Landé g-factor of 0.8

    Highest level:
    J is given by 5/2
    S is still 1/2
    Therefore L is 3
    This gives a Landé g-factor of 0.857…

    At the ground state in lanthanum metal, I think it would lose its 5d electron. Therefore having a full 6s shell as its last shell. This would give S=0 (all electrons compensate each other). L=0 (same reasoning) and therefore J=0. This gives a Landé g-factor of 0

    #2304 Score: 0
    jefdryck
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    EDIT:
    the L in highest level of 2D is still 2 (determined by the fact that it is a D multiplet), therefore the landé factor is 1.2

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