# orientation of the dumb-bell to have the lowest energy

homepage Forums the double ring orientation of the dumb-bell to have the lowest energy

Viewing 1 post (of 1 total)
• Author
Posts
• #4137 Score: 0
MarieDeseyn
Participant

1) alpha>0: in this case -alpha is negative, thus we want (2cos^2(t)-sin^2(t)) to be maximal (since then we substract the biggest number of the energy), thus theta = 0° or 180°

2) alpha<0: now -alpha is positive, thus we want (2cos^2(t)-sin^2(t)) to be minimal (since then we add the smallest number to the energy), thus theta = 90° or 270°

3) alpha = 0: in this case there is no corrections and thus all orientations lead to the same energy, which is equal to the monopole energy.

Viewing 1 post (of 1 total)
• You must be logged in to reply to this topic.