p8

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  • #3193 Score: 0
    sanfvers
    Participant

    p. 8 (second paragraph): “If you place it such that the z-direction is parallel to the external field B, the energy difference between the two energy levels for the electron will be 2μzB”

    I’m not sure why 2muzB will be the energy difference between the levels if the z-direction of the total magnetic moment is parallel to the magnetic field.

    #3198 Score: 0
    Manon
    Participant

    It’s comparable to what we have seen and calculated in this course. The formula for the splitted energy levels due to the Zeemann-effect is
    (- µ dot B) with µ = -g(µ_B/hbar)S. Note that B, µ and S are all vectors. If we apply B according to the z-direction, we have vec(B)=B*vec(z) and thus the dot product will result in a [vec(S) dot vec(z)], and we take S quantized along the z-axis, which will result in (m_z hbar). Hope this helps!

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