PAC homepage › Forums › PAC curves without hyperfine interaction › PAC This topic has 0 replies, 1 voice, and was last updated 3 years, 10 months ago by Michiel_M. Viewing 1 post (of 1 total) Author Posts May 11, 2019 at 3:09 pm #2369 Score: 0 Michiel_MParticipant a) Because it is measured using nuclear decay isotopes which decay in an exponential way. b) The chance of emitting a photon to detector 3 is much higher then to detector 2. Author Posts Viewing 1 post (of 1 total) You must be logged in to reply to this topic. Log In Username: Password: Keep me signed in Log In