PAC curves without hyperfine interaction

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  • May 10, 2020 at 4:17 pm #3222 Score: 0
    Benji
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    1a.
    Effectively the difference between decay 1 and decay 2 is the decay of the intermediate state which obeys the decaylaw dN/dt=-lambda*N which results in A(t)=lambda*N_0*e^{-lambda*t}.

    1b.
    The probability of reaching detector 1 or 3 is A and the probability of detector 2 is B. If the spins are aligned parallel to detector 1/3 A>B if the spins are aligned parallel to detector 2 B>A. Having said In this situation that means A²>A*B thus more detected events.

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