If a nucleus is perfectly spherical, then its electric multipole moments are zero if the charge is uniformly distributed inside the nucleus. However, if the charge is distributed non-uniformly, and non-symmetrically, then it might not be zero. In this case, there will be contributions from electric multipole terms.
The electric monopole shift must be zero because there are no electrons inside.
There is no extra Fermi contribution compared to a point nucleus because the Fermi contribution term does not depend on the size of the nucleus.
There might be contribution from the Bohr-Weisskopf effect because it depends on the integral of the hyperfine field and the nuclear moment inside the nucleus. This integral depends on the size of the nucleus.