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Duch case would be in the case of Q = 0; that is, when there is no quadrupole moment. This means that there is no deformation of the nuclei from the spherical shape, in which case there is no dependency of the energy states on the orientation w.r.t electron cloud (spin vector). This seems to be the case as well if the nuclear spin I has the values 0 and 1/2, in which case Q = 0. I would understand this in the case of I = 0 as there is no orientation preference for the nucleus, but this is not clear for me in the case of I = 1/2.
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