Sign of hyperfine field at Sr

[AndreasCeulemans]

From the fitting of the peaks, one obtains the frequency of the incoming rmf photons. Next calculate the energy of these photons by multiplying by hbar (E=freq*hbar). Since this is at resonance, the energy of the photons corresponds to the hyperfine splitting g*B*µ_n. Now B is composed from the applied external field B0 and the induced field dB. From equating the energies B can be determined and by substracting the known B0, dB can be determined.

[AndreasCeulemans]

Since the resonance frequency is lower for larger applied fields this means the hyperfine field opposes the applied field and has a negative sign

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