Spherical nucleus homepage › Forums › finite size corrections ? › Spherical nucleus This topic has 0 replies, 1 voice, and was last updated 4 years ago by ErwinVanBuylaere. Viewing 1 post (of 1 total) Author Posts March 11, 2019 at 3:16 pm #2036 Score: 0 ErwinVanBuylaereParticipant Yes, because you’ll still have hyperfine interactions. EDIT (to be a bit more elaborate): the Fermi contact contribution will vanish, but there will still be a Bohr-Weisskopf effect This topic was modified 4 years ago by ErwinVanBuylaere. Author Posts Viewing 1 post (of 1 total) You must be logged in to reply to this topic. Log In Username: Password: Keep me signed in Log In
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