In both Toy Model 0 and Toy Model A, there is already a additional contribution to the energy levels, due to the monopole shift. Only when we compare Toy Model 0 and A, Toy Model A will have a smaller contribution to the energy levels compared to Toy Model 0, because the radius of its nucleus is larger. So the energy levels of Toy Model A will lay lower than the ones of Toy Model 0.
I correct myself. It is not the radius of the nucleus that matters, but the charge distribution. This distribution in Toy Model A will be lowered because of the presence of electrons in the nucleus.