answer

[fedra_moeykens]

1) I would say the La will change in energy and thus the orientation (spin) would change.
2) With zeeman splitting we have (due to I=1/2) E = m_J *g*mu_N * B
because we only look at delta_m_J = 1–> delta_E = g*mu_N*B = 1*3.152 *10e-8 *eV/T *2T = 6.304 10e-8 eV
With extra hyperfine splitting:
A = mu*Bhf/IJ and mu = g*mu_N*I
E(mI) = -g*mu_N*B0*I + g*mu_N*mI*Bhf/J
E(mI=1/2,mJ =-3/2) = 3/2 *g*mu_N * B +g*mu_N*mI*Bhf/J
= 6.304 10e-8 eV (3/2+ 5/(-3/2)) = -1.156 10e-7 eV

E(mI=1/2,mJ =-1/2) = 1/2 *g*mu_N * B +g*mu_N*mI*Bhf/J = (1/2 + 5/(-1/2))*Ezeeman = -12.608 10e-7 eV

E_diff = 11.452 *10e-7eV ( for both cases )

E(mI=1/2,mJ =1/2) = -1/2 *g*mu_N * B +g*mu_N*mI*Bhf/J = Ezeeman *(-1/2 +5/(1/2))=12.608 *10e-7 eV
E(mI=1/2,mJ =3/2) = Ezeeman *(-3/2 +5/(3/2))=1.156 10e-7 eV

[Author]

Posts