task 2

[sennedebruyn]

we have that delta_E = g mu_B B_0 = 1.6 mu_B T

for the -3/2 –> -1/2 we have that
delta_E1 = deltaE + A/2
delta_E2 = deltaE – A/2

for the -1/2 –> 1/2
delta_E1 = deltaE + A/2
delta_E2 = deltaE – A/2

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