Energy Corrections

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    Since the electrons stay outside the nucleus the Fermi contact contribution will be zero (psi(0) up and down are 0), as does the monopole shift because rho_e(0)=0. However the Bohr-Weisskopf effect is not necesarily 0. This one depends on the size of the nucleus and the distribution of the magnetic moments. So there might still be energy corrections.

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